Question

Given an array of double

1.0 2.0 3.0 ... 10.0 

Output

filter(3,7)  should produce 3.0,4.0,5.0,6.0,7.0

filter(5,7.5) should produce 5.0,6.0,7.0,8.0

filter(6.6,6.7) should produce 6.0,7.0

based on a filter method

public List<Double> filter(double start, double end){
    List<Double> list = Arrays.asList(1.0,2.0,3.0,4.0,5.0,6.0,7.0,8.0,9.0,10.0);
    List<Double> resultList = new ArrayList<Double>(); 

     //search in list for elements such that it includes the lower bounds and upper bound of search
     //i.e. 6.6 should also include 6.0 and 7.0 from the array. 


   return resultList;

}

This seems simple but I have not been able to come up with a solution that I am happy with, hence the question. Any help would be greatly appreciated.

Answer 1

The for-loop solution should be the easiest, as you can use the Math.floor function to get the start of your desired list:

for (double d = Math.floor(start); d <= Math.ceil(end); d += 1.0)
    list.add(d);