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Home/ Questions/Q 7769661
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T16:12:50+00:00 2026-06-01T16:12:50+00:00

Given an array with integers, with each integer being at most n positions away

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Given an array with integers, with each integer being at most n positions away from its final position, what would be the best sorting algorithm?

I’ve been thinking for a while about this and I can’t seem to get a good strategy to start dealing with this problem. Can someone please guide me?

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  1. Editorial Team
    Editorial Team
    2026-06-01T16:12:51+00:00Added an answer on June 1, 2026 at 4:12 pm

    I’d split the list (of size N) into 2n sublists (using zero-based indexing):

    list 0: elements 0, 2n, 4n, …
    list 1: elements 1, 2n+1, 4n+1, …
    …
    list 2n-1: elements 2n-1, 4n-1, …

    Each of these lists is obviously sorted.

    Now merge these lists (repeatedly merging 2 lists at a time, or using a min heap with one element of each of these lists).

    That’s all. Time complexity is O(N log(n)).

    This is easy in Python:

    >>> a = [1, 0, 5, 4, 3, 2, 6, 8, 9, 7, 12, 13, 10, 11]
    >>> n = max(abs(i - x) for i, x in enumerate(a))
    >>> n
    3
    >>> print(*heapq.merge(*(a[i::2 * n] for i in range(2 * n))))
    0 1 2 3 4 5 6 7 8 9 10 11 12 13
    
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