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Home/ Questions/Q 843409
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T06:07:20+00:00 2026-05-15T06:07:20+00:00

Given an Expression<Func<T, object>> (e.g. x => x.Prop1.SubProp), I want to create a string

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Given an

Expression<Func<T, object>> 

(e.g. x => x.Prop1.SubProp), I want to create a string “Prop1.SubProp” for as deep as necessary.

In the case of a single access (e.g. x => x.Prop1), I can easily do this with:

MemberExpression body = (expression.Body.NodeType == ExpressionType.Convert) ? (MemberExpression)((UnaryExpression)expression.Body).Operand : (MemberExpression)expression.Body;
return body.Member.Name;

However, if there is deeper nesting, e.g. x => x.Prop1.SubProp1, this only gets the most deeply nested name, e.g. “SubProp1” instead of “Prop1.SubProp1”

Is there anyway to access the full property path of a lambda expression?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T06:07:21+00:00Added an answer on May 15, 2026 at 6:07 am
    public string GetPath<T>(Expression<Func<T, object>> expr)
    {
        var stack = new Stack<string>();
    
        MemberExpression me;
        switch (expr.Body.NodeType)
        {
            case ExpressionType.Convert:
            case ExpressionType.ConvertChecked:
                var ue = expr.Body as UnaryExpression;
                me = ((ue != null) ? ue.Operand : null) as MemberExpression;
                break;
            default:
                me = expr.Body as MemberExpression;
                break;
        }
    
        while (me != null)
        {
            stack.Push(me.Member.Name);
            me = me.Expression as MemberExpression;
        }
    
        return string.Join(".", stack.ToArray());
    }
    
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