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Home/ Questions/Q 4022692
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T10:30:26+00:00 2026-05-20T10:30:26+00:00

Given an STL container (you may also take boost::unordered_map and boost::multi_index_container into account) that

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Given an STL container (you may also take boost::unordered_map and boost::multi_index_container into account) that is non-contiguous, is it guaranteed that the memory addresses of the elements inside the container never changes if no element is removed, (but new ones can be added)?

e.g.

class ABC { };
//
//...
//
std::list<ABC> abclist;
ABC abc;
abclist.insert(abc);
ABC * abc_ptr = &(*abclist.begin());

In other word will abc_ptr be pointed to abc throughout the execution, if I do not remove abc from abc_list.

I am asking this because I am going to wrap the class ABC in C++/Cli, so I need pointers to the ABC instances in the wrapper class. ABC is a simple class and I want the container to handle the memory. If the answer is no then I will use std::list<ABC*>.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T10:30:27+00:00Added an answer on May 20, 2026 at 10:30 am

    std::list, std::set, and std::map guarantee that the iterators (including simple pointers) will not be invalidated when a new element is added or even removed.

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