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Home/ Questions/Q 971241
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T02:55:53+00:00 2026-05-16T02:55:53+00:00

Given class: class C { public: C() { cout << Dflt ctor.; } C(C&

  • 0

Given class:

class C
{
public:
    C()
    {
        cout << "Dflt ctor.";
    }
    C(C& obj)
    {
        cout << "Copy ctor.";
    }
    C(C&& obj)
    {
        cout << "Move ctor.";
    }
    C& operator=(C& obj)
    {
        cout << "operator=";
        return obj;
    }
    C& operator=(C&& obj)
    {
        cout << "Move operator=";
        return obj;
    }
};

and then in main:

int main(int argc, char* argv[])
{
    C c;
    C d = c;
    C e;
    e = c;
    return 0;
}

as you will see from the output the “regular” version of copy ctor and operator= are invoked but not those with rvalue args. So I would like to ask in what circumstances will the move ctor and operator=(C&&) be invoked?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T02:55:54+00:00Added an answer on May 16, 2026 at 2:55 am

    The move constructor will be invoked when the right-hand side is a temporary, or something that has been explicitly cast to C&& either using static_cast<C&&> or std::move.

    C c;
    C d(std::move(c)); // move constructor
    C e(static_cast<C&&>(c)); // move constructor
    C f;
    f=std::move(c); // move assignment
    f=static_cast<C&&>(c); // move assignment
    C g((C())); // move construct from temporary (extra parens needed for parsing)
    f=C(); // move assign from temporary
    
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