Question

given:

def psum(a,b,c):
    return a**b+c

and x = [1,2] and y = 3
how can I do psum(*x,3) –> an equivalent.

I do not want to do x[0], x[1] because a function returns x and calling it twice would be inefficient. Could one do z = function(a). where z = x. and then do z[0], z[1].

But I’m wondering if one can do this otherwise and use positional arguments in such a way.

Also, without using a wrapper.

Edit: One cannot use names because I didn’t implement the function and the function writers did not use named arguments :/

Answer 1

You can do this:

psum(*x + [y])