Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 4615938
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 22, 20262026-05-22T01:54:41+00:00 2026-05-22T01:54:41+00:00

Given I have a IEnumerable (e) and a single value of T (t). What

  • 0

Given I have a IEnumerable (e) and a single value of T (t). What is the simplest way of doing:

IEnumerable<T> newCollection = t+e

At the moment I am doing:

ItemArray = Enumerable.Repeat<object>(t, 1).Concat(e);

which is rather unreadable, since I’am doing not real repeat here.
I also tried:

IEnumerable<T> newCollection = new List<object> { t}.Concat(e);

But this one creates an unecessary List object which also isn’t optimal.

Does anyone have a better idea?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-22T01:54:42+00:00Added an answer on May 22, 2026 at 1:54 am

    Jon Skeet’s answer is the most semantically valuable. However, if you still want a way to do it inline, you can use an implicitly-typed array:

    newCollection = new[] { t }.Concat(e);
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Suppose I have a given object of type IEnumerable<string> which is the return value
Given that I have an IEnumerable<T> , where T is any object, how can
Given you have the following class (bad C#, but you get the drift): public
Given I have a master branch and a other branch. In the other branch
Given I have two File objects I can think of the following implementation: public
given i have the following block of code (function(){ var mb = { abc:function(){
Given: I have an interface. I have only class that implements that interface. Question:
Given I have a class with two constructors: public class TestClass { ObjectOne o1;
I have given a location defined by latitude and longitude. Now i want to
I have given a table background image using css background-image property. The cells are

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.