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Home/ Questions/Q 8530805
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T09:20:13+00:00 2026-06-11T09:20:13+00:00

Given I have a php script of arbitrary complexity, running on an apache2 webserver,

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Given I have a php script of arbitrary complexity, running on an apache2 webserver, and I want to check that this script outputs only valid xhtml.

One way to achieve this that occurred to me was validating the output of this php script IN the script every time it is run, and storing generated errors and warnings in a mysql database.

Is this possible?

Thanks!

EDIT: I guess the main problem here is getting the output of the current script without rewriting every echo call.

EDIT2: I’d prefer the w3c sgml validation over html tidy.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-11T09:20:14+00:00Added an answer on June 11, 2026 at 9:20 am

    You can not only check but also fix common errors using tidy

    Example from http://www.php.net/manual/en/tidy.parsestring.php

    <?php
    ob_start();
    ?>
    
    <html>
      <head>
       <title>test</title>
      </head>
      <body>
       <p>error<br>another line</i>
      </body>
    </html>
    
    <?php
    
    $buffer = ob_get_clean();
    $config = array('indent' => TRUE,
                    'output-xhtml' => TRUE,
                    'wrap' => 200);
    
    $tidy = tidy_parse_string($buffer, $config, 'UTF8');
    
    $tidy->cleanRepair();
    echo $tidy;
    ?>
    

    This will output:

    <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
        "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
    <html xmlns="http://www.w3.org/1999/xhtml">
      <head>
        <title>
          test
        </title>
      </head>
      <body>
        <p>
          error<br />
          another line
        </p>
      </body>
    </html>
    
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