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Home/ Questions/Q 6199991
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T04:17:15+00:00 2026-05-24T04:17:15+00:00

Given: interface ViewableDTO {//methods here} class PersonDTO implements ViewableDTO {//implementation here} This works fine:

  • 0

Given:

interface ViewableDTO {//methods here}

class PersonDTO implements ViewableDTO {//implementation here}

This works fine:

PersonDTO p = new PersonDTO();
ViewableDTO v = p; //works

How come this doesn’t work:

List<PersonDTO> plist = getPersonDtoList();
List<ViewableDTO> vlist = plist; //compilation error
List<ViewableDTO> vlist = (List<ViewableDTO>)plist; //compilation error

My solution here is to do this:

List<ViewableDTO> vlist = new ArrayList<ViewableDTO>();
vlist.addAll(plist);

My question is, is this the only / best way to do it?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T04:17:16+00:00Added an answer on May 24, 2026 at 4:17 am

    Consider what you can do with a List<ViewableDTO>. You can add any object of a type implementing ViewableDTO. Do you really want this to compile?

    List<PersonDTO> plist = getPersonDtoList();
    List<ViewableDTO> vlist = plist;
    vlist.add(new OtherDTO());
    

    ?

    No – it’s only safe to get things out of the list in that form, so you use something like this:

    List<PersonDTO> plist = getPersonDtoList();
    List<? extends ViewableDTO> vlist = plist;
    

    See the Java Generics FAQ section on Wildcard Instantiations for more details.

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