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Home/ Questions/Q 991545
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T06:07:37+00:00 2026-05-16T06:07:37+00:00

Given: myvar=Hello echo $myvar -> Shows Hello (fine so far) echo $myvar#world -> shows

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Given:

myvar=Hello
  • echo $myvar -> Shows Hello (fine so far)
  • echo $myvar#world -> shows Hello#world (why? I thought it would complain that here is no such variable called myvar#world)
  • echo ${myvar#world} -> shows just Hello (again, why?)
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T06:07:37+00:00Added an answer on May 16, 2026 at 6:07 am

    The second case splits up into three parts:

    [echo] [$myvar][#world]
     1      2       3
    

    Part 1 is the command, part 2 is a parameter, and part 3 is a string literal. The parameter stops on r since the # can’t be part of the variable name (#’s are not allowed in variable names.)

    The shell parser will recognise the start of a parameter name by the $, and the end by any character which cannot be part of the variable name. Normally only letters, numbers and underscores are allowed in a variable name, anything else will tell the shell that you’re finished specifying the name of the variable.

    All of these will print out $myvar followed by six literal characters:

    echo $myvar world
    echo $myvar?world
    echo $myvar#world
    

    If you want to put characters which can be part of a parameter directly after the parameter, you can include braces around the parameter name, like this:

    myvar=hello
    echo ${myvar}world
    

    which prints out:

    helloworld
    

    Your third case is substring removal, except without a match. To get it to do something interesting, try this instead:

    myvar="Hello World"
    echo ${myvar#Hello }
    

    which just prints World.

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