Question

Given:

namespace One {
  void foo(int x) {
    munch(x + 1);
  }
};

namespace Two {
  // ... see later
}

...
void somewhere() {
  using namespace Two;
  foo(42);
  ...

is there any difference between the following two variants:

a)

namespace Two {
  void foo(int x) {
    munch(x + 1);
  }
};

and b)

namespace Two {
  using One::foo;
};

EDIT: It’s pretty clear that (a) duplicates the code which should never be a good idea. The question is more about overload resolution etc. … what if there are other foos or munches in possibly other namespaces?

Answer 1

With a, they are actually different functions, but with b, the two functions are identical:

assert(&One::foo == &Two::foo);

This would rarely matter; a bigger concern is duplicating the logic.