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Home/ Questions/Q 6377311
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T01:51:19+00:00 2026-05-25T01:51:19+00:00

Given some sample data.xml file: <?xml version=1.0 encoding=utf-8?> <data> <categories> <category id=google> <name>Google</name> </category>

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Given some sample data.xml file:

<?xml version="1.0" encoding="utf-8"?>
<data>
    <categories>
        <category id="google">
            <name>Google</name>
        </category>
    <categories>
    <display>
        <categories>
            <category idref="google"/>
        </categories>
    </display>
</data>

And some jquery code to fetch the data.xml file:

$.ajax( {
    url: '/data.xml',
    dataType: 'xml',
    success: function( data )
    {
        $data = $( data );
        // fetch categories to display
        $categories = $data.find( 'display > categories > category' );
    }
} );

What is a efficient and compact method to resolve the category elements to which the fetched elements in $categories refer to by their idref attribute?

I’ve come up with something like the following:

$categories.each( function() {
    var $category = $data.find( 'categories > category[id=' + $( this ).attr( 'idref' ) + ']' );
} );

But I thought there might be a more compact way of collecting the elements.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T01:51:19+00:00Added an answer on May 25, 2026 at 1:51 am

    You can create id selectors from the idref attributes:

    var referenced = $.unique($categories.map(function() {
        var $found = $data.find("#" + $(this).attr("idref"));
        return ($found.length ? $found[0] : null);
    }).get());
    

    The code above uses map() and $.unique() to build an array containing unique instances of all the referenced <category> elements.

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