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Home/ Questions/Q 8630231
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T09:01:05+00:00 2026-06-12T09:01:05+00:00

Given table T with columns: ID UNIQUEIDENTIFIER CreatedDate DATETIME XmlData XML Where XmlData is

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Given table T with columns:

ID UNIQUEIDENTIFIER
CreatedDate DATETIME
XmlData XML

Where XmlData is structured like:

<application>
    <details firstname="first" lastname="last">
        <statement>statement</statement>
    </details>
    <educationHistory>
        <education subject="subject1" />
        <education subject="subject2" />
    </educationHistory>
    <experienceHistory>
        <examiningExperienceHistory>
            <examiningExperience module="module1" />
            <examiningExperience module="module2" />
        </examiningExperienceHistory>
        <teachingExperienceHistory>
            <teachingExperience module="module1" />
            <teachingExperience module="module2" />
        </teachingExperienceHistory>
    </experienceHistory>
</application>

I need to return an extract like so:

ID Date       FirstName LastName Education    ExaminingExp TeachingExp
-----------------------------------------------------------------------
1  02-10-2012 First     Last     <xmlextract> <xmlextract> <xmlextract>

So far I have:

SELECT ID,
       CreatedDate [Date],
       XmlData.value('(application/details/@firstname)[1]','varchar(max)') [FirstName],
       XmlData.value('(application/details/@lastname)[1]','varchar(max)') [LastName]
FROM T

I’m struggling with thee last three columns. For each record, I need to list teaching/examining experience, and education. Can anybody help?

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  1. Editorial Team
    Editorial Team
    2026-06-12T09:01:06+00:00Added an answer on June 12, 2026 at 9:01 am

    Use .query to extract xml.

    eg

    select 
    XmlData.query('/application/educationHistory/*'),
    XmlData.query('/application/experienceHistory/examiningExperienceHistory/*'),
    XmlData.query('/application/experienceHistory/teachingExperienceHistory/*')
    
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