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Home/ Questions/Q 550557
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T11:18:03+00:00 2026-05-13T11:18:03+00:00

Given that I have m non-empty distinct sets (labeled Z[ 1 ], Z[ 2

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Given that I have m non-empty distinct sets (labeled Z[ 1 ], Z[ 2 ], …, Z[ m ]), I aim to compute the sum of all possible subsets where there is exactly one element from each set. The size of each subset is defined to be the product of its members. For example:

Z[ 1 ] = {1,2,3}

Z[ 2 ] = {4,5}

Z[ 3 ] = {7,8}

Should result in:


1*4*7 + 1*4*8 + 1*5*7 + 1*5*8 + 2*4*7 + 2*4*8 + 2*5*7 + 2*5*8 + 3*4*7 + 3*4*8 + 3*5*7 + 3*5*8 = 810

While this is easy to code (in any language), is this a restatement of the famous subset sum problem? If not, please provide a polynomial time algorithm that computes this sum (pseudo-code or python preferred!). If no polynomial time algorithm exists please explain why.

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  1. Editorial Team
    Editorial Team
    2026-05-13T11:18:03+00:00Added an answer on May 13, 2026 at 11:18 am

    It is easy to see that (1 + 2 + 3) * (4 + 5) * (7 + 8) = 810.

    >>> from operator import mul
    >>> from functools import reduce
    >>> z = [{1,2,3}, {4,5}, {7,8}]
    >>> s = reduce(mul, (sum(zz) for zz in z))
    >>> s
    810
    

    What's the Python function like sum() but for multiplication? product()?

    I personally think that Guido made a terrible decision regarding mul.

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