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Home/ Questions/Q 835991
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T04:54:39+00:00 2026-05-15T04:54:39+00:00

Given that it’s valid to write a = b = c = 2; It

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Given that it’s valid to write

a = b = c = 2;

It would also be nice, rather than

bool allTwo = a == 2 && b == 2 && c == 2;

to instead write

bool allTwo = a == b == c == 2;

But I can’t since a == b evaluates to a boolean which can’t then be compared to an integer.

Is there a language-design reason it has been implemented this way?

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  1. Editorial Team
    Editorial Team
    2026-05-15T04:54:40+00:00Added an answer on May 15, 2026 at 4:54 am

    The type of the expression a == b is boolean, so you would either have to break a rule that an expression means the same thing whatever its context, or have n-ary == operators so that a == b == c is parsed as (== a b c) rather than (== (== a b) c). Which then means you need to have (a == b) == c to compare the boolean c to the result of (a == b), which is OK, but not the simple C style of grammar which C# is in the tradition of.

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