Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
Given that:
Logical addresss space=16
bits Physical address space=16
bits Page size=2K
How the logical address 1027 will be mapped to physical address for the following page table?
p f 0 9 1 7 2 3
Thank You!
address
1027maps top 0because1027 % 2048(2K)=1027 floor(1027/2048)=0. So 1027 maps to1027th byte of page 0in virtual address.Page 0 Virtual Address is mapped to frame number 9 according to page table.
frame 9 has a base address of
9 * 2048 = 18432. Frame 9 has a base address of 18342 in the physical memory.Now
1027th byte of frame 9 is at 18342 + 1027 = 19369address of the physical memory.change the numbers to binary and you have your answer.
See this answer and follow the link given there to understand the concept.
Cheers …