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Home/ Questions/Q 6745341
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T12:11:35+00:00 2026-05-26T12:11:35+00:00

Given the following: <a id=moveElementUp>Move Up</a> <a id=moveElementDown>Move Dowm</a> <div id=elementHolder> <a id=element-1>1</a> <a

  • 0

Given the following:

<a id="moveElementUp">Move Up</a>
<a id="moveElementDown">Move Dowm</a>

<div id="elementHolder">
    <a id="element-1">1</a>
    <a id="element-2">2</a>
    <a id="element-3">3</a>
    <a id="element-4">4</a>
</div>

<script type="text/javascript">
    function reOrder (el){
        // Change IDs of Elements to be Sequential
    }
    $('#moveElementUp').click(function(e){
        // Move Clicked Element Up One Spot in List

        reOrder();
    });
    $('#moveElementDown').click(function(e){
        // Move Clicked Element Down One Spot in List

        reOrder();
    });
</script>

What is the optimal (and fastest) way of going about changing the order of the elements and changing the IDs of all elements to maintain sequential order using jQuery?

Any help would be greatly appreciated!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T12:11:35+00:00Added an answer on May 26, 2026 at 12:11 pm

    This will let you rearrange items arbitrarily. However, it will remove the spaces between the anchor tags. You can solve this by adding spaces between the anchor tags (as I did here: http://jsfiddle.net/FqwDc/1/ ), or by using nested divs instead.

    var $sel; // anchor last clicked on
    var prefixstr = "element-";
    
    $('a[id^="'+prefixstr+'"]').click(function(e) {
        $sel = $(this);
    });
    $('#moveElementUp').click(function(e) {
        // Move Clicked Element Up One Spot in List
        $sel.prev().before($sel);
        changeIDs($('#elementHolder'));
    });
    $('#moveElementDown').click(function(e) {
        // Move Clicked Element Down One Spot in List
        $sel.next().after($sel);
        changeIDs($('#elementHolder'));
    });
    
    function changeIDs($j) { // renumber the IDs
        $j.children('a').each(function(i) {
            $(this).attr('id',prefixstr+i);
        });
    }
    
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