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Home/ Questions/Q 6359223
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T23:29:24+00:00 2026-05-24T23:29:24+00:00

Given the following code all_options = { 1: /test/1, 2: /test/2, 3: /test/3 }

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Given the following code

all_options = { "1": "/test/1", "2": "/test/2", "3": "/test/3" }
selected_options = [ "1", "3" ]

How do I get the entries from all_options where the key matches an entry in selected_options?

I started down the path of using a List Comprehension, but I’m stuck on the last clause:

final = ()
[ final.append(option) for option in all_options if ... ]

Thank you

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T23:29:25+00:00Added an answer on May 24, 2026 at 11:29 pm

    Just like this?

    >>> dict((option, all_options[option]) for option in selected_options if option in all_options)
    {'1': '/test/1', '3': '/test/3'}
    

    From Python 2.7 and 3 onwards, you can use the dict comprehension syntax:

    {option : all_options[option] for option in selected_options if option in all_options}
    

    Or if you just want the values:

    >>> [all_options[option] for option in selected_options if option in all_options]
    ['/test/1', '/test/3']
    
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