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Home/ Questions/Q 909165
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T16:49:57+00:00 2026-05-15T16:49:57+00:00

Given the following code and the suggestions given in this question , I’ve decided

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Given the following code and the suggestions given in this question, I’ve decided to modify this original method and ask if there are any values in the IEnumarable return it, if not return an IEnumerable with no values.

Here is the method:

public IEnumerable<Friend> FindFriends()
{
    //Many thanks to Rex-M for his help with this one.
    //https://stackoverflow.com/users/67/rex-m

    return doc.Descendants("user").Select(user => new Friend
    {
        ID = user.Element("id").Value,
        Name = user.Element("name").Value,
        URL = user.Element("url").Value,
        Photo = user.Element("photo").Value
    });
}

Since everything is inside the return statement, I don’t know how I could do this. Would something like this work?

public IEnumerable<Friend> FindFriends()
{
    //Many thanks to Rex-M for his help with this one.
    //https://stackoverflow.com/users/67/rex-m
    if (userExists)
    {
        return doc.Descendants("user").Select(user => new Friend
        {
            ID = user.Element("id").Value,
            Name = user.Element("name").Value,
            URL = user.Element("url").Value,
            Photo = user.Element("photo").Value
        });
    }
    else
    { 
        return new IEnumerable<Friend>();
    }
}

The above method doesn’t work, and in fact it’s not supposed to; I just feel it illustrates my intentions. I feel I should specify that the code doesn’t work because you can’t create an instance of an abstract class.

Here is the calling code, I don’t want it to receive a null IEnumerable at any time:

private void SetUserFriends(IEnumerable<Friend> list)
{
    int x = 40;
    int y = 3;

    foreach (Friend friend in list)
    {
        FriendControl control = new FriendControl();
        control.ID = friend.ID;
        control.URL = friend.URL;
        control.SetID(friend.ID);
        control.SetName(friend.Name);
        control.SetImage(friend.Photo);

        control.Location = new Point(x, y);
        panel2.Controls.Add(control);

        y = y + control.Height + 4;
    } 
}

Thank you for your time.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T16:49:58+00:00Added an answer on May 15, 2026 at 4:49 pm

    You can use list ?? Enumerable.Empty<Friend>(), or have FindFriends return Enumerable.Empty<Friend>()

    This can be found under the System.Linq namespace.

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