Question

Given the following code :

(define (g x y) (* x y)) 

(define (f x y z)
   (define (h x y)(g (+ x y) x z))h)

Notice that I pass 3 arguments into g ,where g accepts only 2 .

However ,no error message is presented from the interpreter , why ?

Regards

Answer 1

You aren’t actually calling h here, only returning it. Properly formatted your code should look like:

(define (f x y z)
    (define (h x y)
        (g (+ x y) x z))
    h)

So when you call (f 1 2 3) you get back h. If you call

((f 1 2 3) 1 2)

then the interpreter will give an error.