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Home/ Questions/Q 980233
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T04:20:57+00:00 2026-05-16T04:20:57+00:00

Given the following code, I would expect it to return float = 32000.0001. But

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Given the following code, I would expect it to return “float = 32000.0001”. But instead, it returns “float = 32000.0”.

System.out.println("float = "+Float.parseFloat("32000.0001"));

Is there something I can do to prevent/control the rounding? I want the full value returned with no rounding.

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  1. Editorial Team
    Editorial Team
    2026-05-16T04:20:57+00:00Added an answer on May 16, 2026 at 4:20 am

    A float has only 24 bits of precision, which is insufficient to hold the number of digits in your value. The rounding is not due to the parse but to the size of the number. You must use a double if you require floating point, or use BigDecimal if you need arbitrary precision.

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