Home/ Questions/Q 6564299
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-05-25T13:56:57+00:00

Given the following code in RUBY, I need to loop through a bunch of

  • 0

Given the following code in RUBY, I need to loop through a bunch of hashes. The problem is, varX is a string, I need it to be a variable. Any ideas?

element1_old = {:ip => "192.168.0.191", :state => "PA", :county => "ambler"}
element1_new = {:ip => "192.168.0.191", :state => "PA", :county => "warrington"}
element2_old = {:ip => "192.168.0.192", :state => "PA", :county => "ambler"}
element2_new = {:ip => "192.168.0.192", :state => "PA", :county => "ambler"}
element3_old = {:ip => "192.168.0.200", :state => "PA", :county => "warrington"}
element3_new = {:ip => "192.168.0.200", :state => "PA", :county => "ambler"}

for i in 1..3
    var1 = "element#{i}_old"
    var2 = "element#{i}_new"
    p element"#{i}".not_in_both("element#{i}_old") 
end
Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. Editorial Team

    Throw the hashes into another hash:

    h = {
    'element1_old' => {:ip => "192.168.0.191", :state => "PA", :county => "ambler"},
    'element1_new' => {:ip => "192.168.0.191", :state => "PA", :county => "warrington"},
    'element2_old' => {:ip => "192.168.0.192", :state => "PA", :county => "ambler"},
    'element2_new' => {:ip => "192.168.0.192", :state => "PA", :county => "ambler"},
    'element3_old' => {:ip => "192.168.0.200", :state => "PA", :county => "warrington"},
    'element3_new' => {:ip => "192.168.0.200", :state => "PA", :county => "ambler"}
}

for i in 1..3
    old = h["element#{i}_old"]
    new = h["element#{i}_new"]
    p new.not_in_both(old)
end

    I’m assuming that element"#{i}" is actually supposed to be element"#{i}"_new in your pseudo-Ruby example and that you have monkey patched not_in_both into Hash.

    • 0