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Home/ Questions/Q 615435
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T18:13:11+00:00 2026-05-13T18:13:11+00:00

Given the following code @interface MyClass { SomeObject* o; } @property (nonatomic, retain) SomeObject*

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Given the following code

@interface MyClass
{
   SomeObject* o;
}

@property (nonatomic, retain) SomeObject* o;

@implementation MyClass
@synthesize o;

- (id)initWithSomeObject:(SomeObject*)s
{
   if (self = [super init])
   {
      o = [s retain]; // WHAT DOES THIS DO? Double retain??
   }
   return self
}

@end
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  1. Editorial Team
    Editorial Team
    2026-05-13T18:13:12+00:00Added an answer on May 13, 2026 at 6:13 pm

    It is not a double retain; s will only be retained once.

    The reason is that you’re not invoking the synthesized setter method within your initializer. This line:

    o = [s retain];
    

    retains s and sets o to be equal to s; that is, o and s point to the same object. The synthesized accessor is never invoked; you could get rid of the @property and @synthesize lines completely.

    If that line were:

    self.o = [s retain];
    

    or equivalently

    [self setO:[s retain]];
    

    then the synthesized accessor would be invoked, which would retain the value a second time. Note that it generally not recommended to use accessors within initializers, so o = [s retain]; is the more common usage when coding an init function.

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