Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
Given the following code:
L1 db "word", 0
mov al, [L1]
mov eax, L1
What do the brackets in [L1] represent?
This question is specifically about NASM. The other major flavour of Intel-syntax assembly is MASM style, where brackets work differently when there’s no register involved:
See Confusing brackets in MASM32
[L1]means the memory contents at address L1. After runningmov al, [L1]here, Thealregister will receive the byte at address L1 (the letter ‘w’).