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Home/ Questions/Q 8986911
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T21:39:52+00:00 2026-06-15T21:39:52+00:00

Given the following code: namespace sample { class a { } class b :

  • 0

Given the following code:

namespace sample
{
    class a { }

    class b : a { }

    public class wrapper<T> { }

    class test
    {
        void test1()
        {
            wrapper<a> y = new wrapper<b>();
            //Error 11  Cannot implicitly convert type 'sample.wrapper<sample.b>' to 'sample.wrapper<sample.a>' 
        }
    }
}

Logically speaking, a since b is a, a wrapper<b> is a wrapper<a>. Then why I can’t make this conversion, or how can I make it?

Thanks.

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  1. Editorial Team
    Editorial Team
    2026-06-15T21:39:53+00:00Added an answer on June 15, 2026 at 9:39 pm

    since b is a, a wrapper<b> is a wrapper<a>

    Well, this is not true for .NET generic classes, they can’t be co-variant.
    You can achieve something similar using interface covariance:

    class a { }
    class b : a { }
    
    public interface Iwrapper<out T> { }
    public class wrapper<T> : Iwrapper<T> {}
    
    class test
    {
        void test1()
        {
            Iwrapper<a> y = new wrapper<b>();
        }
    }
    
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