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Home/ Questions/Q 8922351
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T06:48:40+00:00 2026-06-15T06:48:40+00:00

Given the following code: struct Item { std::string name; int someInt; string someString; Item(const

  • 0

Given the following code:

struct Item
{
    std::string name;
    int someInt;
    string someString;
    Item(const std::string& aName):name(aName){}
};
std::unordered_map<std::string, Item*> items;
Item* item = new Item("testitem");
items.insert(make_pair(item.name, item);

The item name will be stored in memory two times – once as part of the Item struct and once as the key of the map entry. Is it possible to avoid the duplication? With some 100M records this overhead becomes huge.

Note:
I need to have the name inside the Item structure because I use the hashmap as index to another container of Item-s, and there I don’t have access to the map’s key values.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T06:48:42+00:00Added an answer on June 15, 2026 at 6:48 am

    OK, since you say you are using pointers as values, I hereby bring my answer back to life.

    A bit hacky, but should work. Basicly you use pointer and a custom hash function

    struct Item
    {
        std::string name;
        int someInt;
        string someString;
        Item(const std::string& aName):name(aName){}
    
        struct name_hash  
        { 
           size_t operator() (std::string* name)
           {
               std::hash<std::string> h;
               return h(*name);
           }
        };
    };
    std::unordered_map<std::string*, Item*, Item::name_hash> items;
    Item* item = new Item ("testitem");
    items.insert(make_pair(&(item->name), item);
    
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