Question

Given the following code:

using System;

namespace Sandbox
{
   class CommandLine
   {
      static void Main()
      {
         String[] args = Environment.GetCommandLineArgs();
         String executable = args[0];
         String[] paramList = getParamList(args);

         System.Console.WriteLine("Directory ....... {0}", Environment.CurrentDirectory);
         System.Console.WriteLine("Executable ...... {0}", args[0]);
         System.Console.WriteLine("Params .......... {0}", String.Join(", ", paramList));
      }

      private static String[] getParamList(String[] args)
      {
         String[] paramList = new String[args.Length - 1];

         for (int i = 1; i < args.Length; i++) 
         {
            int j = i - 1;
            paramList[j] = args[i];
         }

         return paramList;
      }
   }
}

… Saved as commandline.cs and csc’d to commandline.exe

I’d like to get the full path and filename of the execuatable being invoked. This code almost does it, however it’s not 100% accurate:

• if I call it as commandline.exe foo bar baz from the same directory; all is well
• if I call it as commandline foo bar baz from the same directory, I only get the filename sans extension; not what I want
• if I call it as sandbox\commandline foo bar baz from the parent directory; I get the relative path and partial filename

I’m sure there’s a much easier way of getting the full path and filename of the executable other than string manipulation, right?

Answer 1

That will be

System.Diagnostics.Process.GetCurrentProcess().MainModule.FileName

Be aware, though, that when running your application from within Visual Studio, this will most likely return full path to a vshost file.