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Home/ Questions/Q 7029895
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T00:35:55+00:00 2026-05-28T00:35:55+00:00

Given the following code var a = $(‘<div><div></div></div>’); a.css(visibility, visible); a.find(* :visible); I receive

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Given the following code

var a = $('<div><div></div></div>');
a.css("visibility", "visible");
a.find("* :visible");

I receive an empty array [] as a result instead of a div. What am I doing wrong?

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  1. Editorial Team
    Editorial Team
    2026-05-28T00:35:55+00:00Added an answer on May 28, 2026 at 12:35 am

    To check if an element is visible, it must be inserted into the DOM. You also don’t need the * selector. Try this:

    var a = $('<div><div></div></div>'); // create an element
    a.css("visibility", "visible");
    $("BODY").append(a) // Add the element to the DOM first
    a.find(":visible")
    
    alert(a.find(":visible").length); // displays '1'
    
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