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Home/ Questions/Q 7519479
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T01:54:40+00:00 2026-05-30T01:54:40+00:00

Given the following program: #include <stdio.h> int main() { char buf[1024]; scanf(%s, buf); printf(—->

  • 0

Given the following program:

#include <stdio.h>

int main()
{
    char buf[1024];
    scanf("%s", buf);
    printf("----> %s", buf);
    return 0;
}

which is executed as follows:

grep ....| a.out

or

echo ....| a.out

I get a Segmentation fault error. Can anyone explain why?

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  1. Editorial Team
    Editorial Team
    2026-05-30T01:54:40+00:00Added an answer on May 30, 2026 at 1:54 am

    from scanf man:
    s Matches a sequence of non-white-space characters; the next pointer must be a pointer to character array that is long enough to hold the input sequence and the terminating null character (‘\0’), which is added automatically. The input string stops at white space or at the maximum field width, whichever occurs first.

    specifying maximum field width will prevent stack overrun

        scanf("%1023s", buf);
    

    and to ensure stack no overrun on printf use memset:

        memset(buf,0,1024);
    

    so, programm will be:

    #include <stdio.h>
    #include <string.h>
    int main()
    {
        char buf[1024];
        memset(buf,0,1024);
        scanf("%1023s", buf);
        printf("----> %s", buf);
        return 0;
    }
    
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