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Home/ Questions/Q 8845559
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T11:46:14+00:00 2026-06-14T11:46:14+00:00

Given the following schema: (sorry it’s crooked) I’m trying to get back a list

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Given the following schema: (sorry it’s crooked)

Schema

I’m trying to get back a list of activities at a place and a count of how many play that particular activity at that place.

start root = node(0)
> match root-[:HAS_PLACE]->place-[:CAN_PLAY]->activity<-[:CAN_PLAY]-place2<-[?:PLAYS_AT]-user
> where place.Id = 1307
> return activity, count(user)
==> +---------------------------------------------------+
==> | activity                            | count(user) |
==> +---------------------------------------------------+
==> | Node[5]{Name->"Swimming",Id->5}     | 0           |
==> | Node[3]{Name->"Kick Boxing",Id->3}  | 0           |
==> | Node[12]{Name->"Basketball",Id->22} | 0           |
==> | Node[13]{Name->"Handball",Id->23}   | 0           |
==> | Node[6]{Name->"Racquetball",Id->6}  | 0           |
==> | Node[2]{Name->"Aerobics",Id->2}     | 0           |
==> +---------------------------------------------------+
==> 6 rows, 21403 ms 

While I think the above does what I want, taking 21 seconds isn’t a good thing. I believe it’s due to the optional relationship or even backtracking, but how could I make a better query?

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  1. Editorial Team
    Editorial Team
    2026-06-14T11:46:15+00:00Added an answer on June 14, 2026 at 11:46 am

    try:

    start root = node(0)
    match root-[:HAS_PLACE]->place-[:CAN_PLAY]->activity, user-[?:PLAYS_AT]->place
    where place.Id = 1307
    return activity, count(user)
    

    or use an index on the placenodes and do:

    start place = node:places(Id=1307)
    match place-[:CAN_PLAY]->activity, user-[?:PLAYS_AT]->place
    return activity, count(user)
    
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