Question

Given the following strings:

application/pdf; name=a.pdf
application/pdf; name="b.pdf"
application/pdf; name="c.pdf
application/pdf; name=d.pdf"

I need the following values in a capture named “filename”:

a.pdf
b.pdf
c.pdf
d.pdf

The following regex works for a.pdf, but fails for the rest due to the double quotes:

name=(?<filename>.*)

Any suggestions how I can get the rest? Thanks.

Answer 1

Try this one:

/name="?(?<filename>[^"]*)"?/