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Home/ Questions/Q 3280874
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T19:45:12+00:00 2026-05-17T19:45:12+00:00

Given the following table: create table TreeNode ( ID int not null primary key,

  • 0

Given the following table:

create table TreeNode
(
  ID int not null primary key,
  ParentID int null foreign key references TreeNode (ID)
)

How could I write a common table expression to start at the root (WHERE ParentID IS NULL) and traverse its descendants until the result set contains some target node (e.g., WHERE ID = n)? It’s easy to start at the target node and traverse upward to the root, but that wouldn’t generate the same result set. Specifically, nodes having the same parent as the target node wouldn’t be included.

My first attempt was:

with Tree as
(
  select
    ID,
    ParentID
  from
    TreeNode
  where
    ParentID is null
  union all select
    a.ID,
    a.ParentID
  from
    TreeNode a
    inner join Tree b
      on b.ID = a.ParentID
  where
    not exists (select * from Tree where ID = @TargetID)
)

Which gives the error: Recursive member of a common table expression 'Tree' has multiple recursive references.

NOTE: I’m only interested in top-down traversal.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-17T19:45:13+00:00Added an answer on May 17, 2026 at 7:45 pm

    UPDATE 2:

    A third attempt that “traverses” the tree in both directions.

    Build a CTE of all ParentIDs from Target to root. Then, select from tree the nodes whose ID or Parent shows up in the short list.

    --
    ;
    WITH    Tree
              AS ( SELECT   ID
                           ,ParentID
                   FROM     TreeNode
                   WHERE    [ID] = @targetId
                   UNION ALL
                   SELECT   a.ID
                           ,a.ParentID
                   FROM     TreeNode a
                            INNER JOIN Tree b ON b.ParentID = a.ID
                 )
        SELECT  *
        FROM    [dbo].[TreeNode] n
        WHERE  EXISTS (SELECT *
                       FROM [Tree] t
                       WHERE [t].[ID] = [n].[ID]
                             OR [t].[ID] = [n].[ParentID]
                      )
    
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