Question

Given the following table format…

id | date       | value
___|____________|______
11 | 2010-01-01 | 50
11 | 2010-01-02 | 100
12 | 2010-01-01 | 150
12 | 2010-01-02 | 200

… I need to select the id that corresponds to the maximum value on a day that I specify. The only way I’ve figured out how to do this so far is using a sub-query as follows:

SELECT id
    FROM table
    WHERE date =  '2010-01-01'
        AND value = ( 
            SELECT MAX(value)
                FROM table
                WHERE date = '2010-01-01'
                GROUP BY date
        )

On a table with ~70,000 records, with a primary key over id and date, this takes ~0.25 seconds to execute, which seems a long time to me. Is there a faster way for me to achieve the same result?

Thanks.

Answer 1

SELECT TOP 1 id FROM table WHERE date = '2010-01-01' ORDER BY value DESC