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Home/ Questions/Q 8551469
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T14:12:09+00:00 2026-06-11T14:12:09+00:00

Given the following test: [Fact] public void FactMethodName() { var d = 6.4133; var

  • 0

Given the following test:

[Fact]
public void FactMethodName()
{
    var d = 6.4133;
    var actual = d.ToString("R");
    Assert.Equal("6.4133", actual);
}

It is passed on x86 but not on Any CPU or x64:

Assert.Equal() Failure
Position: First difference is at position 5
Expected: 6.4133
Actual:   6.4132999999999996

The question is why that happens? Note that not all double values behave this way.

I understand about issues with floating point. No need to point me to wikipedia. No need to point out that test is incorrect — it just illustrates the problem — change it to Console.WriteLine(..); if you will.

UPDATE I removed mentions of test runners becasue those details turned out to be irrelevant.

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  1. Editorial Team
    Editorial Team
    2026-06-11T14:12:10+00:00Added an answer on June 11, 2026 at 2:12 pm

    I think the secret is in using “R” format string (see more about this)

    “When a Single or Double value is formatted using this specifier, it is first tested using the general format, with 15 digits of precision for a Double and 7 digits of precision for a Single. If the value is successfully parsed back to the same numeric value, it is formatted using the general format specifier. If the value is not successfully parsed back to the same numeric value, it is formatted using 17 digits of precision for a Double and 9 digits of precision for a Single.”

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