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Home/ Questions/Q 833411
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T04:30:50+00:00 2026-05-15T04:30:50+00:00

Given the following text: This is!!xa simple string!xpattern I would like to get a

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Given the following text:

This is!!xa simple string!xpattern

I would like to get a regexp that matches the !x that’s between “string” and “pattern” but not !!xa that’s between “is” and “a”.

This regexp is to be used inside a string split().

I have tried several combinations but I cannot get a regexp that meets my needs. Perhaps my expression is not so regular after all =)

Thanks in advance!


EDIT:

SOLUTION

Just to state clear the solution is going to be:

s.replace(/(([^!])|^)!x/g,'$1SOME_MAGICAL_STRING').split(/SOME_MAGICAL_STRING/)

Thanks for the solution idea to both jvenema and Amarghosh. And also to everyone that provided feedback too.

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  1. Editorial Team
    Editorial Team
    2026-05-15T04:30:51+00:00Added an answer on May 15, 2026 at 4:30 am
    var s = "This is!!xa simple string!xpattern";
    s.replace(/[^!]!x/,'-');
    

    output:

    "This is!!xa simple strin-pattern"
    

    Edit: I missed the g, my bad. This one works:

    var s = "!xThis is!!xa simple string!xpattern";
    s.replace(/(([^!])|^)!x/g,'$1-');
    

    output:

    "-This is!!xa simple string-pattern"
    

    All we’re doing is matching the preceding character and then including it back into the replacement.

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