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Home/ Questions/Q 7674235
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T16:41:37+00:00 2026-05-31T16:41:37+00:00

Given the following tree structure in Haskell: data Tree = Leaf Int | Node

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Given the following tree structure in Haskell:

data Tree = Leaf Int | Node Int Tree Tree deriving Show

How can I get Haskell to return a list of the data in pre-order?

e.g. given a tree:

Node 1 (Leaf 2) (Leaf 3)

return something like:

preorder = [1,2,3]
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  1. Editorial Team
    Editorial Team
    2026-05-31T16:41:38+00:00Added an answer on May 31, 2026 at 4:41 pm

    Ok, sorry about the late reply, but I got this working as follows:

    preorder(Leaf n) = [n]
    preorder(Node n treeL treeR) = [n] ++ preorder treeL ++ preorder treeR'code'
    

    This however does not work for me still

    preorder (Leaf n) = [n]   
    preorder (Node n a b) = n:(preorder a) ++ (preorder b) 
    
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