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Home/ Questions/Q 7980793
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T10:10:49+00:00 2026-06-04T10:10:49+00:00

Given the following: typedef struct{ … … } A; typedef struct{ … … }

  • 0

Given the following:

typedef struct{
...
...
} A;

typedef struct{
...
... 
} B;

typedef union __attribute__((transparent_union)) {
    A a;
    B b;
} C;

If I declare a function

myMethod(C){
...
}

The following is legal without explicit casting:

A myA;
B myB;

meMethod(myA);
myMethod(myB);

(from: “c unions and polymorphism“)

However, why is the following not allowed:

C cArray[2];
c[0]=myA;
c[1]=myB;

This gives an incompatible type error without explicit casting. Is there any way to avoid explicit casting?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-04T10:10:50+00:00Added an answer on June 4, 2026 at 10:10 am

    The GCC documentation states:

    This attribute, attached to a union type definition, indicates that
    any function parameter having that union type causes calls to that
    function to be treated in a special way.

    In other words, the transparency only applies to function parameters.

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