Question

Given the table:
Products(id, price)

How do I write a sql query to return all the productus with the Nth highest price (can be more than one with that proce)

Thanks

Answer 1

This is the most generic I can make this, but it still uses TOP where some RDBMS use LIMIT, so you may need to make slight modificiation.

SELECT
  *
FROM
  Products
WHERE
  price = (
           SELECT
             MIN(price)
           FROM
             (
              SELECT TOP 9 price FROM Products GROUP BY price ORDER BY price DESC
             )
             AS top_9
          )

Other dialects that allow row_number would likely make better options than my nested sub-queries.

EDIT : Typed MAX, meant MIN

EDIT : Someone suggested I give an example using windowing functions…

SELECT
  *
FROM
(
  SELECT
    RANK() OVER (ORDER BY price) AS ranked_position,
    *
  FROM
    Products
)
  AS ranked_products
WHERE
  ranked_position = 9

Or use DENSE_RANK, depending on the behavior you want.

Note : Check your RDBMS for use of windowed functions. Not all are created equal.