Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 630949
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 13, 20262026-05-13T19:54:40+00:00 2026-05-13T19:54:40+00:00

Given these tables table Channel ————– ChannelID int IDENTITY <other irrelevant stuff> table Program

  • 0

Given these tables

table Channel
--------------
ChannelID int IDENTITY
<other irrelevant stuff>

table Program
--------------
ProgramID   int IDENTITY
ChannelID   int
AiringDate  datetime
<other irrelevant stuff>

and this query

SELECT   C.ChannelID, t.AiringDate
FROM 
Channel C
LEFT JOIN ( 
    SELECT distinct ChannelID
    FROM   Program 
    WHERE AiringDate = '2010-01-16'
) p 
        ON p.ChannelID=C.ChannelID 
CROSS JOIN (
    SELECT AiringDate = '2010-01-16'
) t
WHERE   C.ChannelID IN (1, 2, 74, 15, 906)  /* the Channel table contains more channels than we are interested in */
    AND p.ChannelID IS NULL

which yields

ChannelID | AiringDate
----------|-----------
    2     | 2010-01-16
   906    | 2010-01-16

how can I modify it to accept a date range, so that the result will be something like

ChannelID | AiringDate
----------|-----------
    2     | 2010-01-16
   906    | 2010-01-16
    2     | 2010-01-17
   906    | 2010-01-17

if there were no programs aired on these 2 channels any of these two days

This returns no rows

SELECT   C.ChannelID, t.AiringDate
FROM 
Channel C
LEFT JOIN ( 
    SELECT distinct ChannelID, AiringDate
    FROM   Program 
    WHERE AiringDate between '2010-01-16' and '2010-01-17'
) p 
        ON p.ChannelID=C.ChannelID 
CROSS JOIN (
    SELECT AiringDate = '2010-01-16'
    union
    SELECT AiringDate = '2010-01-17'
) t
WHERE   C.ChannelID IN (1, 2, 74, 15, 906) 
    AND p.ChannelID IS NULL

That CROSS JOIN is a bit ugly, and it would be nice to get rid of it altogether. Note that the first example query is a bit convoluted; For single dates I have a simpler one that only outputs missing ChannelIDs:

SELECT   C.ChannelID
FROM 
Channel C
LEFT JOIN ( 
    SELECT distinct ChannelID
    FROM   Program 
    WHERE  AiringDate = '2010-01-16'
) p 
        ON p.ChannelID=C.ChannelID 
WHERE   C.ChannelID IN (1, 2, 74, 15, 906) 
    AND p.ChannelID IS NULL
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-13T19:54:41+00:00Added an answer on May 13, 2026 at 7:54 pm

    If I understand correct, this should get what you requested.

    • Combine all Channels with every AiringDate
    • Select all Channels having AiringDates between the dates you need.
    • LEFT JOIN to remove all Channels already having AiringDates

    SQL Statement

    DECLARE @Channel TABLE (ChannelID INTEGER PRIMARY KEY)
    DECLARE @Program TABLE (ProgramID INTEGER PRIMARY KEY, ChannelID INTEGER, AiringDate DATETIME)
    
    INSERT INTO @Channel VALUES (1) -- Aired on 16 & 17
    INSERT INTO @Channel VALUES (2) -- Aired on 16
    INSERT INTO @Channel VALUES (3) -- Not Aired
    
    INSERT INTO @Program VALUES (1, 1, '01-16-2010')
    INSERT INTO @Program VALUES (2, 1, '01-17-2010')
    INSERT INTO @Program VALUES (3, 2, '01-16-2010')
    
    
    SELECT  C.*
    FROM    (
              SELECT  C.ChannelID 
                      , p.AiringDate 
              FROM    @Channel C        
                      CROSS JOIN ( 
                        SELECT  DISTINCT AiringDate 
                        FROM    @Program 
                        WHERE   AiringDate BETWEEN '01-16-2010' AND '01-17-2010'
                      ) p 
            ) c
            LEFT OUTER JOIN (
              SELECT  C.ChannelID, p.AiringDate
              FROM    @Channel C
                      INNER JOIN @Program p ON p.ChannelID = C.ChannelID
              WHERE   AiringDate BETWEEN '01-16-2010' AND '01-17-2010' 
            ) p ON p.ChannelID = C.ChannelID AND p.AiringDate = C.AiringDate
    WHERE   p.ChannelID IS NULL AND p.AiringDate IS NULL
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 318k
  • Answers 318k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer I found the answer. Apparently if you set the length… May 13, 2026 at 11:52 pm
  • Editorial Team
    Editorial Team added an answer I came across this question yesterday looking for an easy… May 13, 2026 at 11:52 pm
  • Editorial Team
    Editorial Team added an answer Richard Jones has written a library hivex which provides read/write… May 13, 2026 at 11:52 pm

Related Questions

I'm not much of a database guru so I would like some advice. Background
I have a set of records indexed by id numbers, I need to convert
Does anyone know a way to auto-generate database tables for a given class? I'm
I have an application that displays league tables for sporting leagues. These tables are
Let say that I have 2 tables with the same structure : STOCK and

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.