Question

Given this array and a name (e.g. ‘def’), how do I get the containing array, or key?

$all = array(
 '0' => array(
      'name' => 'abc'
      'option' => 1,
    ),
 '1' => array(
      'name' => 'def'
      'option' => 1,
    ),
 '2' => array(
      'name' => 'ghi'
      'option' => 0,
    ),
);

What’s the best way to return this array given ‘def’?

$single = array(
  'name' => 'def'
  'option' => 1,
);

I could do something like this:

$single = array();
foreach ($all as $key => $value) {
  if ($value['name'] == 'def') {
    $single = $all[$key]; 
  }
}

Or prerender the keys in the array so that it looks like this:

$all = array(
 'abc' => array(
      'name' => 'abc'
      'option' => 1,
    ),
 'def' => array(
      'name' => 'def'
      'option' => 1,
    ),
 'ghi' => array(
      'name' => 'ghi'
      'option' => 0,
    ),
);
$single = $all['def'];

But I’m wondering if there’s a shorter php function for that.

Answer 1

You could use array_filter:

array_filter($array, function($var){
   return $var["name"] == "def";
});