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Home/ Questions/Q 5955845
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T18:10:19+00:00 2026-05-22T18:10:19+00:00

Given this code: class Something attr_accessor :my_variable def initialize @my_variable = 0 end def

  • 0

Given this code:

class Something
  attr_accessor :my_variable

  def initialize
    @my_variable = 0
  end

  def foo
    my_variable = my_variable + 3
  end
end

s = Something.new
s.foo

I get this error:

test.rb:9:in `foo': undefined method `+' for nil:NilClass (NoMethodError)
    from test.rb:14:in `<main>'

If attr_accessor creates a method called my_variable (and ..=), why can’t foo find the method? It works if I change it to self.my_variable, but why? Isn’t self the default receiver?

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  1. Editorial Team
    Editorial Team
    2026-05-22T18:10:19+00:00Added an answer on May 22, 2026 at 6:10 pm

    You’re not calling the method there, you’re actually referencing the same variable you’re in the process of defining! This is a little gotcha in Ruby.

    What would be better is if you referenced and set the instance variable instead:

    @my_variable = @my_variable + 3
    

    Or shorter:

    @my_variable += 3
    

    Or you could call the setter method, as you found (and Jits pointed) out:

    self.my_variable += 3
    

    This last one will call the my_variable= method defined by the attr_accessor, where the other two will only modify a variable. If you did it this way, you could override my_variable= to do something different to the value passed in:

    def my_variable=(value)
      # do something here
      @my_variable = value
    end
    

    BONUS

    Or you could call the method explicitly by passing an empty set of arguments through:

    my_variable = my_variable() + 3
    

    This is not “The Ruby Way” to go about it, but it’s still interesting to know that you can still call a method this way if you have a local variable of the same name.

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