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Home/ Questions/Q 186527
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Asked: May 11, 20262026-05-11T15:39:45+00:00 2026-05-11T15:39:45+00:00

Given this code: dgIPs.DataSource = from act in Master.dc.Activities where act.Session.UID == Master.u.ID select

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Given this code:

dgIPs.DataSource =      from act in Master.dc.Activities     where act.Session.UID == Master.u.ID     select new     {       Address = act.Session.IP.Address,       Domain = act.Session.IP.Domain,       FirstAccess = act.Session.IP.FirstAccess,       LastAccess = act.Session.IP.LastAccess,       IsSpider = act.Session.IP.isSpider,       NumberProblems = act.Session.IP.NumProblems,       NumberSessions = act.Session.IP.Sessions.Count()     }; 

How do I pull the Distinct() based on distinct Address only? That is, if I simply add Distinct(), it evaluates the whole row as being distinct and thusly fails to find any duplicates. I want to return exactly one row for each act.Session.IP object.

I’ve already found this answer, but it seems to be a different situation. Also, Distinct() works fine if I just select act.Session.IP, but it has a column I wish to avoid retrieving and I’d rather not have to do this by manually binding my datagrid columns.

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  1. 2026-05-11T15:39:46+00:00Added an answer on May 11, 2026 at 3:39 pm
    dgIPs.DataSource =      from act in Master.dc.Activities     where act.Session.UID == Master.u.ID     group act by act.Session.IP.Address into g     let ip = g.First().Session.IP     select new     {       Address = ip.Address,       Domain = ip.Domain,       FirstAccess = ip.FirstAccess,       LastAccess = ip.LastAccess,       IsSpider = ip.isSpider,       NumberProblems = ip.NumProblems,       NumberSessions = ip.Sessions.Count()     }; 

    Or:

    dgIPs.DataSource =      from act in Master.dc.Activities     where act.Session.UID == Master.u.ID     group act.Session.IP by act.Session.IP.Address into g     let ip = g.First()     select new     {       Address = ip.Address,       Domain = ip.Domain,       FirstAccess = ip.FirstAccess,       LastAccess = ip.LastAccess,       IsSpider = ip.isSpider,       NumberProblems = ip.NumProblems,       NumberSessions = ip.Sessions.Count()     }; 
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