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Home/ Questions/Q 163075
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Asked: May 11, 20262026-05-11T11:30:13+00:00 2026-05-11T11:30:13+00:00

Given this data 34 foo 34 bar 34 qux 62 foo1 62 qux 78

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Given this data

34 foo 34 bar 34 qux 62 foo1 62 qux 78 qux  

I want to replace the string at 2nd column into ” if it is ‘qux’. Resulting:

34 foo 34 bar 34  62 foo1 62  78   

How do you do that with sed? In particular the data is very big with ~10^7 lines

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  1. 2026-05-11T11:30:14+00:00Added an answer on May 11, 2026 at 11:30 am

    I wouldn’t actually do it with sed since that’s not the best tool for the job. The awk tool is my tool of choice whenever somebody mentions columns.

    cat file | awk '$2 == 'qux' { print $1 } $2 != 'qux' { print $0 }' 

    or the simplest form:

    cat file | awk '{ if ($2 == 'qux') {$2 = ''}; print }' 

    If you must use sed:

    cat file | sed 's/  *qux *$//' 

    making sure that you use the correct white space (the above uses only spaces).

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