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Home/ Questions/Q 101437
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Asked: May 11, 20262026-05-11T00:46:16+00:00 2026-05-11T00:46:16+00:00

Given this field: char lookup_ext[8192] = {0}; // Gets filled later And this statement:

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Given this field:

char lookup_ext[8192] = {0}; // Gets filled later 

And this statement:

unsigned short *slt = (unsigned short*) lookup_ext; 

What happens behind the scenes?

lookup_ext[1669] returns 67 = 0100 0011 (C), lookup_ext[1670] returns 78 = 0100 1110 (N) and lookup_ext[1671] returns 68 = 0100 0100 (D); yet slt[1670] returns 18273 = 0100 0111 0110 0001.

I’m trying to port this to C#, so besides an easy way out of this, I’m also wondering what really happens here. Been a while since I used C++ regularly.

Thanks!

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  1. 2026-05-11T00:46:16+00:00Added an answer on May 11, 2026 at 12:46 am

    The statement that you show doesn’t cast a char to an unsigned short, it casts a pointer to a char to a pointer to an unsigned short. This means that the usual arithmetic conversions of the pointed-to-data are not going to happen and that the underlying char data will just be interpreted as unsigned shorts when accessed through the slt variable.

    Note that sizeof(unsigned short) is unlikely to be one, so that slt[1670] won’t necessarily correspond to lookup_ext[1670]. It is more likely – if, say, sizeof(unsigned short) is two – to correspond to lookup_ext[3340] and lookup_ext[3341].

    Do you know why the original code is using this aliasing? If it’s not necessary, it might be worth trying to make the C++ code cleaner and verifying that the behaviour is unchanged before porting it.

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