Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 856437
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 15, 20262026-05-15T08:14:08+00:00 2026-05-15T08:14:08+00:00

Given two vectors X and Y , I have to find their correlation, i.e.

  • 0

Given two vectors X and Y, I have to find their correlation, i.e. their linear dependence/independence. Both vectors have equal dimension. The result should be a floating point number from [-1.0 .. 1.0].

Example:

X=[-1, 2,    0]
Y=[ 4, 2, -0.3]

Find y = cor(X,Y) such that y belongs to [-1.0 .. 1.0].

It should be a simple construction involving a list-comprehension. No external library is allowed.

UPDATE: ok, if the dot product is enough, then here is my solution:

nX = 1/(sum([x*x for x in X]) ** 0.5)
nY = 1/(sum([y*y for y in Y]) ** 0.5)
cor = sum([(x*nX)*(y*nY)  for x,y in zip(X,Y) ])

right?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-15T08:14:09+00:00Added an answer on May 15, 2026 at 8:14 am

    Sounds like a dot product to me.

    Solve the equation for the cosine of the angle between the two vectors, which is always in the range [-1, 1], and you’ll have what you want.

    It’s equal to the dot product divided by the magnitudes of two vectors.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Given any two sequences/vectors of M real numbers, I can easily compute their closeness
Assume we have two numeric vectors x and y . The Pearson correlation coefficient
Given: two images of the same subject matter; the images have the same resolution,
Given two model classes, Foo and Bar , I want Foo to have 3
I have two vectors in a game. One vector is the player, one vector
Suppose I have two vectors of values: a <- c(1,3,4,5,6,7,3) b <- c(3,5,1,3,2) And
I have two vectors A B which are coupled, I mean that they define
I have a program that find coordinates between two point with a predefined interval:
Given two orthogonal unit vectors, A and B, and two different orthogonal unit vectors
Given two strings text1 and text2 : public SOMEUSABLERETURNTYPE Compare(string text1, string text2) {

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.