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Home/ Questions/Q 1098767
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T00:37:46+00:00 2026-05-17T00:37:46+00:00

Given: x = [‘a’,’b’,’c’,’d’,’e’] y = [‘1′,’2′,’3’] I’d like iterate resulting in: a, 1

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Given:

x = ['a','b','c','d','e']
y = ['1','2','3']

I’d like iterate resulting in:

a, 1
b, 2
c, 3
d, 1
e, 2
a, 3
b, 1

… where the two iterables cycle independently until a given count.

Python’s cycle(iterable) can do this w/ 1 iterable. Functions such as map and itertools.izip_longest can take a function to handle None, but do not provide the built-in auto-repeat.

A not-so-crafty idea is to just concatenate each list to a certain size from which I can iterate evenly. (Boooo!)

Suggestions? Thanks in advance.

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  1. Editorial Team
    Editorial Team
    2026-05-17T00:37:47+00:00Added an answer on May 17, 2026 at 12:37 am
    import itertools
    x = ['a','b','c','d','e']
    y = ['1','2','3']
    for a, b in itertools.izip(itertools.cycle(x), itertools.cycle(y)):
        print a, b
    
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