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Home/ Questions/Q 6834499
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T23:07:08+00:00 2026-05-26T23:07:08+00:00

Going through a tutorial for android (related to multithreading, loopers and handlers), i came

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Going through a tutorial for android (related to multithreading, loopers and handlers), i came across this:

public synchronized void enqueueDownload(final DownloadTask task)

My questions are:

  1. When and why is it needed to declare a parameter of a function as final?
  2. Is it specific to Java or does something similar exist in other languages such as C/C++?
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  1. Editorial Team
    Editorial Team
    2026-05-26T23:07:09+00:00Added an answer on May 26, 2026 at 11:07 pm

    In Java this is usually so that you can access the parameter within an anonymous inner class – which is often used in Android for event handlers and the like.

    The real meaning is that the parameter’s value cannot be changed within the method, but the purpose is usually for anonymous inner classes…

    public synchronized void enqueueDownload(final DownloadTask task) {
        SomethingHandler handler = new SomethingHandler() {
            @Override public void handleSomething() {
                // This would not compile if task were not final
                task.doSomething();
            }
        };
        // Use handler
    }
    
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