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Home/ Questions/Q 208181
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T17:48:08+00:00 2026-05-11T17:48:08+00:00

Good Day All we are trying to do is inside a trigger make sure

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Good Day

All we are trying to do is inside a trigger make sure the user is not inserting two fees that have ‘alone’ in the name. Those fees need to be handled individually.

For some reason, it appears the top section of sql quit working two weeks ago. To get around it I recoded it the second way and get the correct results. What I am confused is why would the first portion seemed to have worked for the last several years and now it does not?

SELECT  @AloneRecordCount = count(*) 

FROM  inserted i 
      INNER JOIN deleted d on i.id = d.id 

WHERE  i.StatusID = 32 
      AND d.StatusID <> 32 
      AND i.id IN  
      (SELECT settlementid FROM vwFundingDisbursement fd
      WHERE fd.DisbTypeName LIKE  '%Alone'
      AND fd.PaymentMethodID = 0)


SELECT  @AloneRecordCount = count(i.id) 

FROM    inserted i INNER JOIN
        deleted d on i.id = d.id
        JOIN vwFundingDisbursement fd on i.id = fd.settlementid

WHERE   i.StatusID = 32 
        AND d.StatusID <> 32  
        AND fd.DisbTypeName like '%Alone'
        AND fd.PaymentMethodID = 0

this is on SQL Server 2005
there is no error, instead the top statement will only return 1 or zero
while the bottom statement will return the actual number found.

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  1. Editorial Team
    Editorial Team
    2026-05-11T17:48:08+00:00Added an answer on May 11, 2026 at 5:48 pm

    A schema (or at least how the view is created) would help, but here’s a guess…

    If you are looking for multiple rows in vwFundingDisbursement with the value “Alone” in the distribution type name, then a JOIN is going to return multiple rows as your source table (INSERTED) joins to multiple rows in the view. If you use IN though, SQL doesn’t care if it returns multiple matches, it’s only going to give you one row.

    As an example:

    CREATE TABLE dbo.Test_In_vs_Join1
    (
         my_id     INT     NOT NULL
    )
    
    CREATE TABLE dbo.Test_In_vs_Join2
    (
         my_id     INT     NOT NULL
    )
    
    INSERT INTO dbo.Test_In_vs_Join1 (my_id) VALUES (1)
    INSERT INTO dbo.Test_In_vs_Join1 (my_id) VALUES (2)
    INSERT INTO dbo.Test_In_vs_Join1 (my_id) VALUES (3)
    INSERT INTO dbo.Test_In_vs_Join1 (my_id) VALUES (4)
    INSERT INTO dbo.Test_In_vs_Join1 (my_id) VALUES (5)
    
    INSERT INTO dbo.Test_In_vs_Join2 (my_id) VALUES (1)
    INSERT INTO dbo.Test_In_vs_Join2 (my_id) VALUES (1)
    INSERT INTO dbo.Test_In_vs_Join2 (my_id) VALUES (2)
    INSERT INTO dbo.Test_In_vs_Join2 (my_id) VALUES (3)
    INSERT INTO dbo.Test_In_vs_Join2 (my_id) VALUES (3)
    
    SELECT
         T1.my_id,
         COUNT(*)
    FROM
         dbo.Test_In_vs_Join1 T1
    INNER JOIN dbo.Test_In_vs_Join2 T2 ON
         T2.my_id = T1.my_id
    GROUP BY
        T1.my_id
    
    SELECT
         T1.my_id,
         COUNT(*)
    FROM
         dbo.Test_In_vs_Join1 T1
    WHERE
        T1.my_id IN (SELECT T2.my_id FROM dbo.Test_In_vs_Join2 T2)
    GROUP BY
        T1.my_id
    

    On a side note, burying a column inside of another column like this is a violation of the normalized form and just asking for problems. Performing this kind of business logic in a trigger is also a dangerous path to go down as you’re finding out.

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