Question

Good day.

I have row in database:

When i make first select:

SELECT * FROM `table` WHERE `name` Like '%Коляска \"Balmoral\" Silver Cross%'

i get null(num rows = 0)…
But if i make second select:

SELECT * FROM `products` WHERE `name` Like '%Balmoral%'

i get num rows = 1.

Why not work first select and how make right select?

Slashes in database and in select becose i use mysql_real_escape_string when i insert new row and use select

Answer 1

Use this:

SELECT *  FROM `titles` WHERE `title` LIKE '%Коляска \\\\"Balmoral\\\\%" Silver Cross'

Explanation: the \ must be escaped with \ for SQL, but for PHP we need extra \ for escaping also.

Or Simply:

SELECT *  FROM `titles` WHERE `title` = 'Коляска \\"Balmoral\\" Silver Cross'

However, I don’t know why!!!