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Home/ Questions/Q 8711487
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T04:53:27+00:00 2026-06-13T04:53:27+00:00

Good day, I’m having a ton of trouble with the following php code, the

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Good day,

I’m having a ton of trouble with the following php code,
the pseudo code for it as follow:

Check if a relationship exists in the table
if it doesn’t exist add a relationship to the table.
otherwise get the current relationship and return it.

the code goes as follow:

    $result = mysql_query("SELECT * FROM friends WHERE (user_id = '" .$me. "' AND user_id2 = '" .$other. "') OR (user_id2 = '" .$me. "' AND user_id = '" .$other. "')");
if($result == false){
    mysql_query("INSERT INTO `friends`(`user_id`, `user_id2`, `status`) VALUES ('" .$me. "', '" .$other. "', 'pending')");
    echo("Friend Request Sent"); 
}
else{
    $res = mysql_query("SELECT 'status' FROM friends WHERE (user_id = '" .$me. "' AND user_id2 = '" .$other. "')");
    $rows = array();
    while($r = mysql_fetch_assoc($res)) {
        $rows[] = $r;
    }
    echo json_encode($rows); 

}

Thanks in advance

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T04:53:28+00:00Added an answer on June 13, 2026 at 4:53 am

    you should try the below if condition

    if(mysql_num_rows($result)){
         mysql_query("INSERT INTO `friends`(`user_id`, `user_id2`, `status`) VALUES ('" .$me. "', '" .$other. "', 'pending')");
         echo("Friend Request Sent"); 
    }
    

    and also else block should be same as first query, and it should look like

    else{
        $res = mysql_query("SELECT 'status' FROM friends WHERE (user_id = '" .$me. "' AND user_id2 = '" .$other. "') OR (user_id2 = '" .$me. "' AND user_id = '" .$other. "')") ;
        $rows = array();
        while($r = mysql_fetch_assoc($res)) {
           $rows[] = $r;
        }
        echo json_encode($rows); 
    }
    
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